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15p^2+26p+8=0
a = 15; b = 26; c = +8;
Δ = b2-4ac
Δ = 262-4·15·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*15}=\frac{-40}{30} =-1+1/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*15}=\frac{-12}{30} =-2/5 $
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